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Yahoo!奇摩知識+ - 分類問答 - 科學常識 - 發問中
有關於一個三角函數的比例
Jul 14th 2013, 01:51

現有一直角三角形ABC AB為垂直 BC為底 AC為斜邊

已知三角形內AB線上有一點畫一條直線連接到AC 為R

現已知R跟BC直線為多少

他們的比例是否是R:BC=A>直線連接的點長度:AC全長?

記得是有這個公式還是比例 只是有點忘了

如果要求AC 要怎麼求?

其實他是一個4分之1圓 半徑為BC AC延伸出圓外 AB也是 AB是延伸出+半徑

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